Class 12th sumita arora solutions || Chapter 1- Python Revision tour - 1 || Type-B

Q 1. Fill In the missing lines of code in the following code. The code reads in a limit amount a prices and prints the largest price that is less than the limit. You can assume that all prices and the limit are positive numbers. When a price 0 is entered the program terminates and prints the largest price that is less than the limit.

# Read the limit.

limit = float(input ('enter the limit'))

max_price = 0

#Read the next price

next_price = float(input ("Enter a price or to stop:"))

while next_price > 0 :

<write your code here>

# Read the next price

<Write your code here>

if max_price > 0 :

<Write your code here>

else :

<Write your code here>

Answer =

# Read the limit.
limit = float(input ('enter the limit'))
max_price = 0
#Read the next price
next_price = float(input ("Enter a price or to stop:"))
while next_price > 0 :
    if next_price > max_price and next_price < limit :
        max_price = next_price
    # Read the next price
    next_price = float(input ("Enter a price or to stop:"))
if max_price > 0 :
    print("Largest number :-",max_price)
else :
    print("Invalid")

Q. Predict the outputs of the following programs: -

(a)

count = 0

while count < 10 :

print ("Hello")

count += 1

(b)

x = 10

y = 0

while x > y :

print (x, y)

x = x - 1

y += 1

(c)

keepgoing = True

x = 100

while keepgoing :

print (x)

x = x - 10

if x < 50 :

keepgoing = False

(d)

x = 45

while x < 50 :

print (x)

(e)

for x in [1,2,3,4,5] :

print (x)

(f)

for p in range(1, 10) :

print (p)

(g)

for z in range (-500, 500, 100) :

print (z)

(h)

x = 10

y = 5

for i in range (x - y * 2) :

print ("%", i)

(i)

c = 0

for x in range (10) :

for y in range (5) :

c += 1

print (c)

(j)

x = [1,2,3]

counter = 0

while counter < len(x) :

print(x [counter] * '%' )

for y in x :

print(y ' ')

counter += 1

(k)

for x in 'lamp' :

print(str.upper(x))

(l)

x = 'one'

y = 'two'

counter = 0

while counter < len(x) :

print ( x[counter], y[counter])

counter += 1

(m)

x = "apple, pear, peach"

y = x.split(", ")

for z in y :

print(z)

(n)

x = 'apple, pear, peach, grapefruit'

y = x. split(', ' )

for z in y :

if z < 'm' :

print(str.lower(z))

else :

print(str.upper(z))

Answer =

(a)

Output:-

Hello

>>>

(b)

Output: -

10 0

9 1

8 2

7 3

6 4

>>>

(c)

Output: -

100

>>>

(d)

Output: -

45 infinite times.

(e)

Output: -

>>>

(f)

Output: -

>>>

(g)

Output: -

-500

-400

-300

-200

-100

100

200

300

400

>>>

(h)

It will give no output, because precedence of * operator is more than - operator.

So for value in range become zero after solving.

(i)

Output: -

>>>

(j)

* *

* * *

* *

* * *

%%%

* *

* * *

>>>

(k)

>>>

(l)

o t

n w

e o

>>>

(m)

apple

pear

peach

>>>

(n)

apple

PEAR

PEACH

grapefruit

>>>

Q. Find and write the output of the following python code:

for Name in ['Jayes', 'Ramya', 'Taruna', 'Suraj'] :

print (Name)

if Name[0] == 'T' :

break

else :

print("Finished!")

print ('Got it!')

Answer =

Jayes

Finished!

Ramya

Finished!

Taruna

Got it!

>>>

Q4. How many times will the following for loop execute and what's the output?

(i)

for i in range(-1, 7, -2) :

for j in range (3) :

print(1, j)

(ii)

for i in range (1, 3, 1) :

for j in range (i+1) :

print('*')

Answer =

(a)

There is no output because of invalid range command.

(b)

This program execute 5 times

Output -

>>>

Q. Is the loop in the code below infinite? How do you know (for sure) before you run it?

m = 3

n = 5

while n < 10 :

m = n - 1

n = 2 * n - m

print(n, m)

Answer =

This program execute finite because while loop have condition (n<10). So when n become greater than 10 then program break.

GUPTA MECHANICAL

Sunday, 8 November 2020