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Wednesday, 29 June 2022

[Solution] Adjacent Sum Parity CodeChef Solution


Chef has an array A of length N.

Chef forms a binary array B of length N using the parity of the sums of adjacent elements in A. Formally,

  • Bi=(Ai+Ai+1)%2 for 1iN1
  • BN=(AN+A1)%2

Here x%y denotes the remainder obtained when x is divided by y.

Chef lost the array A and needs your help. Given array B, determine whether there exits any valid

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 array A which could have formed B.

Input Format

  • The first line contains a single integer T — the number of test cases. Then the test cases follow.
  • The first line of each test case contains an integer N — the size of the array A.
  • The second line of each test case contains N space-separated integers B1,B2,,BN denoting

  •  the array B.

Output Format

For each testcase, output YES if there exists a valid array ANO otherwise.

You can print any character in any case. For example YESYesyEs are all considered same.

Constraints

  • 1T1000
  • 2N105
  • Bi{0,1}
  • The sum of N over all test cases do not exceed 3105

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